Question

A 4.7 kg bag of groceries is in equilibrium on
an incline of 28. What is the magnitude of the normal force
on the bag?
Answer in units of N

Answer 1

Question

The normal force in the given conditions will be equal to:

$$N = m \cdot g \cdot \cos \alpha = 4.7 \cdot 9.8 \cdot \cos 28{}^\circ \approx 40.7 \, N.$$

Answer: $40.7 \, N$.