Answer to Question #181977 in Mechanics | Relativity for ares

Question

a force p directed from point a to point b determine moment of force p about x axis and y axis if it produces a moment of 1000nm about z axis

Answer 1

To be given in question

Force (p)a to b direction apply

Distance (d) =1000nm$=10^{-6} meter$

To be asked in question

Moment =?

We know that

Moment defination given

$P= F.d$

$P=Fdcos\theta$

$F_{z}= F_{1} +F_{2}$

This question given perpendicular distance d=1000 nm

$= F_{1} +F_{2} =F_{z} \longrightarrow(1)$

(F₁+F₂) produced p_z

$\Sigma F= (F_{1} +F_{2})d$

$=(F_{1} +F_{2})d$

Put value equation (1)

$\Sigma P=F_{z}d \longrightarrow(2)$

$\Sigma P=F_{z}\times10^{-6}$ $N meter$