Question

A woman holds a hose 0.8 m above the ground such that the water shoots out horizontally. The water hits the ground at a point 2 m away. What is the speed/velocity with which the water leaves the hose?

Answer 1

A woman holds a hose 0.8 m above the ground such that the water shoots out horizontally. The water hits the ground at a point 2 m away. What is the speed/velocity with which the water leaves the hose?

Solution:

Let:

$$H = 0.8 \, \text{m}$$ $$S = 2 \, \text{m}$$

v–?

S = vt, were t – is the time of free falling water from height H

$$v = \frac{S}{t}$$

Such as: $H = \frac{1}{2} g t^2$, $t = \sqrt{\frac{2H}{g}}$

$$v = S \sqrt{\frac{g}{2H}}$$ $$v = 2 \cdot \sqrt{\frac{9.8}{2 \cdot 0.8}} \approx 2.95 \, \text{m/s}$$

Answer: 2.95 m/s.