Question #180456

a 80 mm crankshaft main bearing journal rotates at 3000 rev/min while carring a normal load w= 20kN. If the coefficient of friction in the bearing =0.02, calculate the power lost in friction at this engine speed


1
Expert's answer
2021-04-13T07:02:31-0400

To be given in question

length=80mm

n=3000rev/min

w=20kN

μ=0.02\mu=0.02

To be asked in question

Power poss in friction Ploss=?P_{loss}=?


We know that



Total friction torque

l=Rcosαl=Rcos\alpha

τ=23μWl\tau =\frac{2}{3}\mu Wl

τ=23×0.02×20×103×80×103N×m\tau=\frac{2}{3} \times0.02\times20\times10^3 \times80\times10^{-3} N\times m

Ploss=21.33WP_{loss}=21.33 W

Ploss=τωP_{loss}=\tau\omega

w=2πnw=2\pi n

w=2π×50w=2\pi \times50

Ploss=21.33×100πP_{loss}=21.33\times100\pi

Ploss=6.697×103WP_{loss}=6.697\times10^3 W



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