Question #18044

After a day of testing race cars you decide to take your own 1550-kg car onto the test track while moving down the track at 10.0m/s you uniformly accelerate to 30.0m/s in 10.0s what is the average net force that the track has applied to the car during the 10.0s interval

Expert's answer

After a day of testing race cars you decide to take your own 1550-kg car onto the test track while moving down the track at 10.0m/s you uniformly accelerate to 30.0m/s in 10.0s what is the average net force that the track has applied to the car during the 10.0s interval

Solution:

Let:


m=1550 kgm = 1550\ \mathrm{kg}v0=10 m/sv_0 = 10\ \mathrm{m/s}v=30 m/sv = 30\ \mathrm{m/s}t=10 st = 10\ \mathrm{s}


F—?

F = ma, were a - acceleration


a=vv0t,a = \frac{v - v_0}{t},F=mvv0tF = m \frac{v - v_0}{t}F=1550301010=3100 NF = 1550 \frac{30 - 10}{10} = 3100\ \mathrm{N}


Answer: the average net force is: 3100 N.

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