Answer to Question #180245 in Mechanics | Relativity for Alex Gregan

Question

A 2500 kg car moving at a speed of 22.0 m s⁻¹ and a 3450 kg van moving at a speed of 15.0 m s⁻¹ are moving at aright angles to each other and collide as shown in the figure above.

The car and van stick together in the collision. What is the speed of the car+van after the collision? (in m s⁻¹ to 3 s.f)

Answer 1

To be given in question

Car velocity $v_{1}$ =22 $Meter/sec$

Car mass $m_{1}$ =2500 kg

Van velocity $v_{2}$ =15 $Meter/sec$

Van mass$m_{2}$ =3450 kg

To be asked in question

Car+van velocity=?

We know that

Momentum conservation law

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V$

$V=\frac {m_{1}v_{1}+m_{2}v_{2}}{m_{1}+m_{2}}$

Put value

$V=\frac{2500\times22+3450\times15}{2500+3450}$

$V=17.9411meter/sec$