Question

An engineer weighs a sample of mercury (ρ =
13.6 × 10
3
kg/m3
) and finds that the weight
of the sample is 8.9 N.
What is the sample’s volume? The acceleration of gravity is 9.81 m/s
2
.
Answer in units of m3

Answer 1

Question

We have:

$$\begin{array}{l} g = 9.81 \frac{m}{s^2} \\ \rho = 13.6 \times 10^3 \frac{kg}{m^3} \\ P = 8.9 \, N \\ \end{array}$$

We will have:

$$P = m \cdot g = \rho \cdot V \cdot g \Rightarrow V = \frac{P}{\rho \cdot g} = \frac{8.9}{13.6 \cdot 10^3 \cdot 9.81} = 73.5 \cdot 10^{-6} \, m^3.$$

Answer: $73.5 \cdot 10^{-6} \, m^3$.