Answer to Question #179692 in Mechanics | Relativity for Thandeka

Question

Jimmy is about to take part in the high dive. He jumps up off the high board at an angle of 23 degrees with an initial velocity of 2.5m/s. How far does Jimmy travel before he hits the water (horizontal distance). Consider air resistance

Answer 1

horizontal distance:

$x=v_xt$

$v_x=v_0cos\theta$

$v_0$ is initial velocity.

$\theta=23\degree$

vertical distance:

$y=v_0tsin\theta-gt^2/2$

When Jimmy hits the water:

$y=0$

$v_0sin\theta=gt/2$

$t=2v_0sin\theta/g=2\cdot2.5sin23\degree/9.8=0.2\ s$

$x=2.5\cdot0.2cos23\degree=0.46\ m$