A car, initially at rest, travels from 0 m/s to 15.2 m/s in 20.3 s. What is the car's acceleration?
The acceleration is
a=dvdt=ΔvΔt=v2−v1t=15.2−020.3=0.7487≈0.75 m/s2\displaystyle a = \frac{dv}{dt} = \frac{\Delta v}{\Delta t} = \frac{v_2 - v_1}{t} = \frac{15.2-0}{20.3}= 0.7487 \approx 0.75 \; m/s^2a=dtdv=ΔtΔv=tv2−v1=20.315.2−0=0.7487≈0.75m/s2
Answer: 0.75 m/s20.75\;m/s^20.75m/s2
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