The period of a 2 kg stone is rotated in a vertical circle on a 2 m cord with the period of 1 s.
Give the magnitude of the radial acceleration in m/s2.
a=ω2r,a=\omega^2r,a=ω2r,
ω=2πT,\omega=\frac{2\pi}{T},ω=T2π,
a=4π2rT2,a=\frac{4\pi^2r}{T^2},a=T24π2r,
a=4⋅3.142⋅212=79 ms2.a=\frac{4\cdot 3.14^2\cdot 2}{1^2}=79~\frac{m}{s^2}.a=124⋅3.142⋅2=79 s2m.
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