Answer to Question #179154 in Mechanics | Relativity for Abraham Yarba

Question #179154

A uniform pencil floats with 8cm of it's length immersed in water. What length is immersed when it floats in a glycerol of density 1.3×10³ kg/m³?(density of water=1.0×10³ kg/m³)


1
Expert's answer
2021-04-09T06:35:57-0400

To be given in question


In Water float

ll =8cm

ρw=1.0×103kg/m3\rho_{w}=1.0\times10^3 kg/m^3

In glycerol float

ρg=1.3×103kg/m3\rho_{g}=1.3\times10^3kg /m^3

To be asked in question

l=?l'=?

We know that formula

[ρwglA]w=[ρgglA]g[\rho_{w}glA]_{w}=[\rho_{g}gl'A]_{g}

ρwl=ρgl\rho_{w}l=\rho_{g}l'

Put value

1.00×103×8=1.3×103×l1.00\times10^3\times8=1.3\times10^3\times l'

l=6.15cml' =6.15 cm


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Comments

Abraham Yarba
09.04.21, 14:56

Thank you very much

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