Answer to Question #178713 in Mechanics | Relativity for Kimberly Nalupta

Question

A student driver steps on the gas to increase her speed from 11 m/s to 15 m/s in 30s. Find her acceleration

Answer 1

Explanations & Calculations

• By the definition of the constant acceleration, this could be evaluated.

$\qquad\qquad \begin{aligned} \small a&=\small \frac{\text{change in velocity}}{\text{elapsed time over that change}}=\text{Rate of change of velocity }\\ &=\small \frac{15\,ms^{-1}-11\,ms^{-1}}{30s}\\ &=\small \bold{0.133\,ms^{-2}} \end{aligned}$