Question

The muzzle velocity of an armor-piercing round fired from an M1A1 tank is 1770 m/s (nearly 4000 mph or mach 5.2). A tank is at the top of a cliff and fires a shell horizontally. If the shell lands 6520 m from the base of the cliff, how high is the cliff?

Answer 1

Question

We have:

$$\begin{array}{l} s = v \cdot t \Rightarrow t = \frac {s}{v} \Rightarrow \\ \Rightarrow h = \frac {g \cdot t ^ {2}}{2} = \frac {g \cdot s ^ {2}}{2 \cdot v ^ {2}} = \frac {9.8 (6520) ^ {2}}{2 (1770) ^ {2}} = 66.5 \text{ m}. \end{array}$$

Answer: 66.5 meters.