Question #17745

A uniform beam XY of length 1 meter supported at P (the pivot) where PX is 20 cm. The beam's weight 5N. What downward force is exerted at X that will make the beam balanced?
Possible Answers: A. 5N , B. 7.5N , C. 12.5N , D 20N.

Expert's answer

Question

We have:


50.3=F0.2F=50.30.2=7.5NAnswer: B) 7.5N.5 \cdot 0.3 = F \cdot 0.2 \Rightarrow F = \frac{5 \cdot 0.3}{0.2} = 7.5 \, \text{N} \Rightarrow \text{Answer: B) } 7.5 \, \text{N}.


Answer: B) 7.5 N.

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