Answer to Question #176844 in Mechanics | Relativity for Catherine Chileshe

Question

A projectile is fired at an angle of 60 degrees with initial velocity of 100m/s find, time of asent, time of flight, maximum height reached, range, maximum possible rang

Answer 1

U_y=100sin(60)

=86.6m/s

U_x=100cos(60)

=50m/s

g=9.8m/s²

Time of ascent = $U_y\div g$

= 8.36 seconds

Time of flight = $2U_y\div g$

= 17.67 seconds

Maximum Height attained = U_y²$\div 2g$

=382.63m

Range = U_xU_y$\div g$

=441.83m

Maximum possible range , it will occur when angle will be 45 degree

Than

Range U_xU_y$\div g$

= 510.35m