A projectile is fired at an angle of 60 degrees with initial velocity of 100m/s find, time of asent
In component form, initial velocity uo=100sin600u_o=100sin60^0uo=100sin600
time of ascent =2uog=2×100sin6009.8=17.67s=\frac{2u_{o}}{g}=\frac{2\times 100sin60^{0}}{9.8}= 17.67s=g2uo=9.82×100sin600=17.67s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments