Question #176843

A projectile is fired at an angle of 60 degrees with initial velocity of 100m/s find, time of asent


1
Expert's answer
2021-03-31T09:38:54-0400

In component form, initial velocity uo=100sin600u_o=100sin60^0

time of ascent =2uog=2×100sin6009.8=17.67s=\frac{2u_{o}}{g}=\frac{2\times 100sin60^{0}}{9.8}= 17.67s


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