A projectile is fired from the surface of the earth with a speed of 200m/s at an angle of 300 above the horizontal. If the ground is level, what is the maximum height reached by the projectile
Let's consider "g \\approx 10 \\; m\/s^2".
The maximum height in projectile motions is
"\\displaystyle h_{max}=\\frac{v_0^2 \\sin^2 \\alpha}{2g} = \\frac{200^2 \\cdot 0.5^2 }{2 \\cdot 10} = \\frac{100^2}{20} = 500 \\,m"
Answer: 500 m
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