What Effort Will Be Required to Lift a Load of 500 N by a Single Movable Pulley? Hint: Mechanical Advantage of a Single Movable Pulley is Two
For the single movable pulley
FF1=2 ⟹ \frac{F}{F_1}=2\impliesF1F=2⟹
F1=F2=5002=250 N.F_1=\frac{F}{2}=\frac{500}{2}=250~N.F1=2F=2500=250 N.
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