A car accelerates from 20 m/s to 30 m/s in 10 s. (a) Calculate the car’s acceleration using v = u + at. (b) Draw a velocity–time graph to show the car’s motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + ½at2
Initial velocity (u)=20 m/s(u)=20\space m/s(u)=20 m/s
Final velocity (v)=30 m/s(v)=30\space m/s(v)=30 m/s
Time taken (t)=10 s(t)=10\space s(t)=10 s
Acceleration =a m/s2= a\space m/s^2=a m/s2
(a) a=v−ut⇒a=1 m/s2(a)\space a=\dfrac{v-u}{t}\\\Rightarrow a=1\space m/s^2(a) a=tv−u⇒a=1 m/s2
(b) (b)\space(b)
Distance covered (s)=Area under the curve=(20×10)+(12×10×10)(s)=Area\space under \space the\space curve=(20\times10)+(\dfrac{1}{2}\times10\times10)(s)=Area under the curve=(20×10)+(21×10×10)
s=250 ms=250\space ms=250 m
(c) s=ut+12at2⇒s=20×10+12×1×100⇒s=250 m(c)\space s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=20\times10+\dfrac{1}{2}\times1\times100\\\Rightarrow s=250\space m(c) s=ut+21at2⇒s=20×10+21×1×100⇒s=250 m
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