Question

A person walks 49 m East and then walks
35 m at an angle 41 North of East.
What is the magnitude of the total dis-
placement?

Answer 1

We will have:

$$\begin{array}{l} d = \sqrt {4 9 ^ {2} + 3 5 ^ {2} - 2 \cdot 4 9 \cdot 3 5 \cdot \cos (1 8 0 {}^ {\circ} - 4 1 {}^ {\circ})} = \\ = \sqrt {2 4 0 1 + 1 2 2 5 + 2 5 8 8 . 6 5 4} = 7 8. 8 \mathrm {m}. \\ \end{array}$$

Answer: 78.8 meters.