Find the greatest angle through which a nonrelativistic alpha partiClec can be deflected by striking a stationary proton.[14°]
Answer
the greatest angle through which a nonrelativistic alpha partiClec can be deflected by striking a stationary proton is given by
"tan\\theta_1=\\frac{sin\\theta }{cos\\theta +m_{\\alpha}\/m_p}\\\\=\\frac{sin14\u00b0 }{cos14\u00b0 +4m_p\/m_p}\\\\=\\frac{0.24}{4.97}\\\\=0.048"
"\\theta_1=2.75\u00b0"
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