Answer to Question #174950 in Mechanics | Relativity for Obada

Question #174950

Find the greatest angle through which a nonrelativistic alpha partiClec can be deflected by striking a stationary proton.[14°]


1
Expert's answer
2021-03-26T11:40:19-0400

Answer

the greatest angle through which a nonrelativistic alpha partiClec can be deflected by striking a stationary proton is given by

tanθ1=sinθcosθ+mα/mp=sin14°cos14°+4mp/mp=0.244.97=0.048tan\theta_1=\frac{sin\theta }{cos\theta +m_{\alpha}/m_p}\\=\frac{sin14° }{cos14° +4m_p/m_p}\\=\frac{0.24}{4.97}\\=0.048

θ1=2.75°\theta_1=2.75°


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