Q2. The altitude of a rocket in the first half-minute of its ascent is given by x=bt2, where x is the altitude and b=2.90m/s2 is a constant.
a) Find a general expression for the rocket's velocity as a function of time.
b) Find the rocket's instantaneous velocity at t=20s.
c) Find an expression for the average velocity of the rocket. Find the average velocity after during the first 20 seconds.
d) Compare your two velocities (instantaneous and average). Is there a difference and if so why?
Solution:
Such as v=dtdX
v=(bt2)′=2btv=2.9∗2t=5.8tv(t=20s)=5.8∗20=116m/sv(average)=2v0+vtv(averaget=20)=2v0+v(t=20)=20+116=58m/s
Answers: v=5.8t, v=116m/s, v(average)=2v0+vt, v(averaget=20)=58m/s
The instantaneous and average velocities are different.