Answer to Question #172921 in Mechanics | Relativity for April

Question

If the density of seawater is 1.03 g/cm3

at the surface, what is its density at a depth where

the pressure is 109 dynes/cm2?

Answer 1

p=109 dynes/cm^2=10.9 Pa,

$h=\frac{p}{\rho g}=\frac{10.9}{1030\cdot 9 .8}=1.08 ~mm,$

This depth is shallow, so destinies are equals.