If the density of seawater is 1.03 g/cm3
at the surface, what is its density at a depth where
the pressure is 109 dynes/cm2?
p=109 dynes/cm^2=10.9 Pa,
h=pρg=10.91030⋅9.8=1.08 mm,h=\frac{p}{\rho g}=\frac{10.9}{1030\cdot 9 .8}=1.08 ~mm,h=ρgp=1030⋅9.810.9=1.08 mm,
This depth is shallow, so destinies are equals.
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