Question #17142

starting from rest, how long does it take moving man to reach a velocity of 5 m/s if his acceleration is 1.75 m/s^2?

Expert's answer

Starting from rest, how long does it take moving man to reach a velocity of 5m/s5\mathrm{m/s} if his acceleration is 1.75m/s21.75\mathrm{m/s}^2?

Solution:

Let:


v=5m/sa=1.75m/s2\begin{array}{l} v = 5 \, \mathrm{m/s} \\ a = 1.75 \, \mathrm{m/s}^2 \\ \end{array}S?S=12at2v=att=vaS=v22aS=5221.75=7.14s\begin{array}{l} S -? \\ S = \frac{1}{2} a t^2 \\ v = a t \Rightarrow t = \frac{v}{a} \\ \Rightarrow \\ S = \frac{v^2}{2a} \\ S = \frac{5^2}{2 \cdot 1.75} = 7.14 \, \mathrm{s} \\ \end{array}


Answer: 7.14 s.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS