A 2-kg disk has a radius of 18 cm and rotates with an angular acceleration of 12 rad/s2
about
an axis through its center and perpendicular to the plane of the disk. Determine the tangential
force at the rim of the disk.
I = "\\frac{1}{2}" MR² = "\\frac{1}{2}" (2)(0.18)²
τ = αI = "\\frac{1}{2}" (2)(0.18)²(12)
τ = FR
F = "\\dfrac{\u03c4}{R}"
F = "\\dfrac{[\\frac{1}{2} \n2\n1\n\u200b\t\n (2)(0.18)\u00b2(12)]}{0.18}" = 2.16 N
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