Question

A 2-kg disk has a radius of 18 cm and rotates with an angular acceleration of 12 rad/s2

about 

an axis through its center and perpendicular to the plane of the disk. Determine the tangential 

force at the rim of the disk.

Answer 1

Solution:

I = $\frac{1}{2}$ MR² = $\frac{1}{2}$ (2)(0.18)²

τ = αI  = $\frac{1}{2}$ (2)(0.18)²(12)

τ = FR

F = $\dfrac{τ}{R}$

F = $\dfrac{[\frac{1}{2} 2 1 ​ (2)(0.18)²(12)]}{0.18}$ = 2.16 N