Question

A lever is used to lift a load of 320Kg. The effort applied is 210 N and it moves through a distance of 1.7 m. The load moves 345mm

Determine the following:

1. Mechanical Advantage
2. Displacement ratio

Answer 1

1)

$MA=\frac{F_2}{F_1}=\frac{mg}{F_1}=\frac{320\cdot 9.8}{210}=15,$

2)

$DR=\frac{d_1}{d_2}=\frac{1.7}{0.345}=4.9.$