A lever is used to lift a load of 320Kg. The effort applied is 210 N and it moves through a distance of 1.7 m. The load moves 345mm
Determine the following:
1)
"MA=\\frac{F_2}{F_1}=\\frac{mg}{F_1}=\\frac{320\\cdot 9.8}{210}=15,"
2)
"DR=\\frac{d_1}{d_2}=\\frac{1.7}{0.345}=4.9."
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