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Answer to Question #17012 in Mechanics | Relativity for trey
Question #17012
A 11.8 N force acts horizontally on a 3.9 kg box sitting on a frictionless surface of ice. Determine the acceleration of the box.
Expert's answer
According to the second Newton's law the acceleration of the box is
a = F/m = 11.8[N] / 3.9[kg] ≈ 3.03 [m/s²].
a = F/m = 11.8[N] / 3.9[kg] ≈ 3.03 [m/s²].
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