Question

The IMA of the pulley system shown in figure 3 is 4, how far must the applied force move it the load moves 1 ft? If the load weighs of 200 lb and the efficiency of the system is 90%, what must be the applied force?

Answer 1

$d_2=IMA\cdot d_1=4\cdot 1=4~ft,$

$F=\frac{mg}{\eta \cdot IMA}=\frac{90.7\cdot 9.8}{0.9\cdot 4}=246.9~N.$