A 112 kg stone boulder rolls down a 67.8 m long ramp with an angle of inclination of 27.7° in 10.3 s. What is the power of gravity on the boulder?
P=At=Fht=Flsinαt=mglsinαt,P=\frac At=\frac{Fh}{t}=\frac{Fl\text{sin}\alpha}{t}=\frac{mgl\text{sin}\alpha}{t},P=tA=tFh=tFlsinα=tmglsinα,
P=112⋅9.8⋅67.8⋅0.4610.3≈3.3 kW.P=\frac{112\cdot 9.8\cdot 67.8\cdot 0.46}{10.3}\approx 3.3~\text{kW}.P=10.3112⋅9.8⋅67.8⋅0.46≈3.3 kW.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments