Question #169366

What is the kinetic energy of a thrown 13.2 N stick moving at 3.89 m/s?


1
Expert's answer
2021-03-08T08:24:01-0500

13.2 N = 1.34 kg

Kinetic energy Ek=12mv2E_k = \frac{1}{2}mv^2

=12×1.34×(3.89)2=10.13  J= \frac{1}{2} \times 1.34 \times (3.89)^2 \\ = 10.13 \;J

Answer: 10.13 J


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