What is the kinetic energy of a thrown 13.2 N stick moving at 3.89 m/s?
13.2 N = 1.34 kg
Kinetic energy Ek=12mv2E_k = \frac{1}{2}mv^2Ek=21mv2
=12×1.34×(3.89)2=10.13 J= \frac{1}{2} \times 1.34 \times (3.89)^2 \\ = 10.13 \;J=21×1.34×(3.89)2=10.13J
Answer: 10.13 J
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