Question #169183

used to raise an object of mass 30 kg. If the plane is 

inclined 5° above the horizontal and the coefficient of friction is 0.20, calculate the ideal 

mechanical advantage, actual mechanical advantage, and the efficiency of this machine.


Expert's answer

Angle of inclination(θ)(\theta) = 5°5\degree

Ideal Mechanical Advantage = cosecθcosec\theta = 11.47

Since, the coefficient of friction = 0.20

Actual Mechanical Advantage = cosecθ1+μ=11.471.20=9.56\dfrac{cosec\theta}{1+\mu}=\dfrac{11.47}{1.20}=9.56

Efficiency of the machine = 9.5611.47×100=83.36%\dfrac{9.56}{11.47}\times100=83.36\%


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