Question #16861

A sinusoidal wave is described by
y (x, t) = 2.0 sin (2.11x − 3.62t) cm
where x is the position along the wave propagation. Determine the amplitude, wave
number, wavelength, frequency and velocity of the wave.

Expert's answer

A sinusoidal wave is described by


y(x,t)=2.0sin(2.11x3.62t)cmy (x, t) = 2.0 \sin (2.11x - 3.62t) \, \text{cm}


where xx is the position along the wave propagation. Determine the amplitude, wave number, wavelength, frequency and velocity of the wave.

Solution

the amplitude A=2.0cmA = 2.0 \, \text{cm}

wave number k=2.111cmk = 2.11 \frac{1}{\text{cm}}

wavelength λ=2πk=2π2.11=2,99cm\lambda = \frac{2\pi}{k} = 2 * \frac{\pi}{2.11} = 2,99 \, \text{cm}

frequency f=ω2π=3.622π=0.58Hzf = \frac{\omega}{2\pi} = \frac{3.62}{2\pi} = 0.58 \, \text{Hz}

velocity of the wave v=ωk=3.622.11=1,71cmsv = \frac{\omega}{k} = \frac{3.62}{2.11} = 1,71 \, \frac{\text{cm}}{\text{s}}

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