We have,
Initial angular velocity, ωo\omega_oωo = 3 rev/s
Final angular velocity, ω\omegaω = 0
Time t = 18 sec
Using first equation of circular motion,
ω=ωo+αt\omega = \omega_o + \alpha tω=ωo+αt
0=3+α×180 = 3 + \alpha\times 180=3+α×18
α=−0.166rev/s2\alpha = -0.166 rev/s^2α=−0.166rev/s2
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