An egg rolls off the edge of a table 1.2-meter-high and strikes the floor at a
point 2 meter horizontally from the edge of the table.
Answer
Using
For time t=2hg=2×1.210=0.49sect=\sqrt{\frac{2h}{g}}\\=\sqrt{\frac{2\times1.2}{10}}\\=0.49sect=g2h=102×1.2=0.49sec
Now speed of rolls is given by
v=distancetime=20.49=4.08m/sv=\frac{distance}{time}=\frac{2}{0.49}=4.08m/sv=timedistance=0.492=4.08m/s
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