A spring is fixed to a wooden board with 2 masses suspend from it. The spring has stretched 6 cm. If m1 = 13 kg and m2 = 3 kg, what is the spring constant of the spring?
Stretch in spring "x=6cm=0.06m"
Tw masses "m_1=13kg,m_2=3kg"
Let k be the spring constant -
Then Restoration force in the spring "F=kx=0.06k~~~~~~-(1)"
Then Weight of masses = "(m_1+m_2)g=(13+3)(9.8)"
"=16\\times 9.8=156.8N~~~~~-(2)"
From eqn.(1) and (2) we have-
"0.06k=156.8\\Rightarrow k=\\dfrac{156.8}{0.06}=2613.33N\/m"
hence The spring Constant is 2613.33N/m.
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