Question #16703
a 3 kg cart starting from rest on a frictionless surface is pulled by a horizontal mass-less rope with a constant force of 6 N. What is the acceleration of the cart, and how fast is it moving at the end of two seconds?
Expert's answer
According to the second Newton's law, the acceleration of a cart is
a = F/m = 6[N]/3[kg] = 2[m/s²]
After two seconds the velocity of a cart is
V = at = 2[m/s²]*2[s] = 4[m/s].
a = F/m = 6[N]/3[kg] = 2[m/s²]
After two seconds the velocity of a cart is
V = at = 2[m/s²]*2[s] = 4[m/s].
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#340153 on Dec 2023
#340153 on Dec 2023
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