A juggler throws a ball with an initial horizontal velocity of +1.1 m/s and an initial vertical velocity of +5.7 m/s. What is its acceleration at the top of its flight path? Make sure to consider the sign when responding. Consider the upward direction as positive
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Expert's answer
2011-02-24T05:09:49-0500
The acceleration remains constant during all time of flight of the ball and equals to -g = -9.8 m/s2 (downward)& if we assume the upward direction as positive.
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