Question

A bicyclist increases her speed from 4.0 m/s to 6.0 m/s. The combined mass of the bicyclist and the bicycle is 55 kg. How much work did the bicyclist do in increasing her speed?

Answer 1

Answer

The work is equivalent to change in kinetic energy

$E=W=\frac{m(v_f^2-v_i^2) }{2}$

$=\frac{55(6^2-4^2) }{2}\\=550Joule$