Question

A record on a turntable is spinning and coming to rest. Att = 0s the angular velocity of the record is 20.0rad / s with a constant acceleration df - 5.00rad / (s ^ 2) What the record's angular velocity at t = 0.500 s?

Answer 1

At t = 0 s,

Angular velocity, $\omega_o=20rad/s$

Angular acceleration, $\alpha = 5rad/s^2$

At t = 0.500 s,

$\omega=\omega_o+\alpha t$

$\Rightarrow\omega=20+5\times0.500$

$\Rightarrow \omega=22.5rad/s$