A space telescope in orbit around the Earth discovers a new planet, which is observed to move around the Sun by an angle of 4.72 milliradians in a year. Assuming a circular orbit, estimate the distance, in A.U., of the planet from the Sun
D=206265p=2062654.72⋅10−3=43.7⋅106 AU.D=\frac{206265}{p}=\frac{206265}{4.72\cdot 10^{-3}}=43.7\cdot 10^6~\text{AU}.D=p206265=4.72⋅10−3206265=43.7⋅106 AU.
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