A truck off the from rest and cover a distance of 120m on a straight road in 20 second
Total distance covered(s) = 120 m
Time taken(t) = 20 s
Initial velocity of particle(u) = 0 m/s
Final velocity(v) = "\\dfrac{s}{t}=\\dfrac{120}{20}m\/s"
= "6m\/s"
Acceleration = "\\dfrac{v-u}{t}=\\dfrac{6}{20}m\/s^2"
= "0.3m\/s^2"
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