A truck off the from rest and cover a distance of 120m on a straight road in 20 second
Total distance covered(s) = 120 m
Time taken(t) = 20 s
Initial velocity of particle(u) = 0 m/s
Final velocity(v) = st=12020m/s\dfrac{s}{t}=\dfrac{120}{20}m/sts=20120m/s
= 6m/s6m/s6m/s
Acceleration = v−ut=620m/s2\dfrac{v-u}{t}=\dfrac{6}{20}m/s^2tv−u=206m/s2
= 0.3m/s20.3m/s^20.3m/s2
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