a 6 kg cart on a level surface is pulled at a constant velocity of 2 m/s by a constant force of 10 N. What is the friction force opposing the motion?
1
Expert's answer
2012-10-17T10:01:52-0400
As the velocity of a cart is constant (i.e. acceleration is equal to zero), the friction force is equal to the pulling force. Therefore, friction force has a magnitude of 10 N.
Comments
Leave a comment