Question #164641

A 100.0 kg football player moving at 8.0 m/s [N] smashes into a training dummy for 0.25 s and bounces back with a velocity of 6.0 m/s [S]. Find the average net force and average acceleration on the football player. 


Expert's answer

FavgΔt=m(vf−vi),F_{avg}\Delta t=m(v_f-v_i),Favg=m∣(vf−vi)∣Δt,F_{avg}=\dfrac{m|(v_f-v_i)|}{\Delta t},Favg=100 kg⋅∣(−6 ms−8 ms)∣0.25 s=5600 N,F_{avg}=\dfrac{100\ kg\cdot|(-6\ \dfrac{m}{s}-8\ \dfrac{m}{s})|}{0.25\ s}=5600\ N,aavg=Favgm=5600 N100 kg=56 ms2.a_{avg}=\dfrac{F_{avg}}{m}=\dfrac{5600\ N}{100\ kg}=56\ \dfrac{m}{s^2}.
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