Question #164176

A 1.00 m3 box is filled with 54.1 moles of air (MM = 0.0289 kg/mole). The rms speed of the molecules is 549 m/s. What is the pressure of the molecules? 


1
Expert's answer
2021-02-16T15:56:41-0500
p=Nmv23Vp=\frac {Nmv^2}{3V}


m=ν×MM=54.1×0.0289=1.56kgm=\nu\times MM=54.1\times0.0289=1.56 kg

N=ν×NA=54.1×6.02×1023=3.26×1025N=\nu\times N_A=54.1\times 6.02\times10^{23}=3.26\times10^{25}


p=3.26×1025×1.56×5493×1=9.3×1027Pap=\frac {3.26\times 10^{25} \times 1.56 \times 549}{3\times 1}=9.3\times10^{27} Pa


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