Question #163804

The blood was flowing out from the heart at the speed of 0.45 m/s through aorta. The diameter of aorta is 1.6 cm. The aorta was splitted into a number of tiny blood vessels. The blood flows through the vessels to various organs with the speed of 5 x 10-5 m/s. If the diameters of the blood vessels are 99.95% smaller than diameter of aorta and the blood is incompressible. Calculate the number of blood vessels in human body by assuming that all the blood vessels have similar diameter.


Expert's answer

Solution:

The flow rate through Aorta, Q₁ = v₁A₁

Q₁ = v₁𝜋(d12\frac{d₁}{2})²


Q₁ = V1πd124\dfrac{V_1\pi d_1^2}{4}


The flow rate through one tiny blood vessel, Q₂ = v₂A₂


Q2 = v2𝜋(d22\frac{d_2}{2})²


Q2 = V2πd224\dfrac{V_2\pi d_2^2}{4}


Given d₂ = d₁ - 99.95%d₁

d₂ = 0.0005d₁


Q2=V2π(0.0005d1)24Q_2=\dfrac{V_2 \pi(0.0005d_1)^2}{4}


Q2=(2.5∗10−7)V2πd124Q_2=\dfrac{(2.5*10^{-7})V_2\pi d_1^2}{4}


A number of tiny blood vessels:


Q1Q2=V1πd124(2.5∗10−7)V2πd124=V1(2.5∗10−7)V2=  0.45(ms)(2.5∗10−7)(5∗10−5(ms))=3.6∗1010\dfrac{Q_1}{Q_2}=\dfrac{\dfrac{V_1\pi d_1^2}{4}}{\dfrac{(2.5*10^{-7})V_2\pi d_1^2}{4}}=\dfrac{V_1}{(2.5*10^{-7})V_2}=\\\;\\\dfrac{0.45(\frac{m}{s})}{(2.5*10^{-7})(5*10^{-5}(\frac{m}{s}))}=3.6*10^{10}






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