Answer to Question #163796 in Mechanics | Relativity for Sage Topaz

Question

ONE GRAM OF GOLD CAN BE BEATEN OUT INTO A FOIL 1.O M2 IN AREA. HOW MANY ATOMS THICK IS SUCH A FOIL? THE MASS OF GOLD ATOM IS 3.27 x 10^-25 KG , DENSITY OF GOLD 1.9 X 10⁴ KG.

Answer 1

Given quantities:

$m = 1g \space\space\space\space\space S = 1m^2 \space\space\space\space \rho = 19000 \large\frac{kg}{m^3}$ $m_o=$ 3.27 x 10^-25 KG

$N = \large\frac{m}{m_o}$ $= \frac{1*10^{-3}}{3.27*10^{-25}}=3*10^{21}$