Question

A wheel is spinning at 5.38 rad/s, and has an angular momentum of 4.05 kg.m2/s. What is its moment of inertia?

Answer 1

From the definition of angular momentum, we have:

$$L=I\omega,$$ $$I=\dfrac{L}{\omega}=\dfrac{4.05\ \dfrac{kg\cdot m^2}{s}}{5.38\ \dfrac{rad}{s}}=0.75\ kg\cdot m^2.$$