Question #163000

A 50 g bracelet is suspected of being gold plated lead instead of pure gold, when it is dropped into a full glass of water, 4.0 cm3 of water overflows. Is the bracelet pure gold? If not, what is the percentage of gold in it? Density of gold is 19 g/cm3  density of lead is 11 g/cm3  



1
Expert's answer
2021-02-15T00:57:08-0500

(a) The volume of water displaced equals the volume of the bracelet. Then, we can find the density of the bracelet:


ρ=mV=50 g4.0 cm3=12.5 gcm3.\rho=\dfrac{m}{V}=\dfrac{50\ g}{4.0\ cm^3}=12.5\ \dfrac{g}{cm^3}.

The density of gold equals 19 gcm319\ \dfrac{g}{cm^3}, therefore, the bracelet isn't made of pure gold.

(b) Let the fraction of gold be xx. Then, we can write the following equation:


19x+11(1x)=12.5,19x+11(1-x)=12.5,8x=1.5,8x=1.5,x=1.58×100%=18.75%.x=\dfrac{1.5}{8}\times100\%=18.75\%.

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