Answer to Question #162998 in Mechanics | Relativity for Sage Topaz

Question

Eating banana enable a person to perform about 40,000 J of work.  Assuming 25 % efficient of the human body to process the energy content of the banana, to what height does eating a banana enable a 60 kg person to climb?  

Answer 1

$Work$ $done$$(w.d)=$ $40,000J$

$Efficiency$ $(E)$ $=$ $25$%

$mass$$(m)$ $=60kg$

$solution$

$w.d=f*d$

considering that the efficiency of human body is $25$%,

hence therefore, the work ouput is given by:

$w.d=25/100*40000$

$=10,000J$

Now from the formula of the work done

$w.d=f*d$

$however,$ $the$ $person$ $is$ $climbing$ $against$ $the$ $gravity$

where $force=mass$ $*acceration$ $due$ $to$ $gravity$

$hence$

$w.d=m*a*d$

$where$ $d=height(h)$

$10,000=60*9.8*h$

$h=10,000/588$

$h=17.01m$