A person standing at the edge of a cliff kicks a stone over the edge with a speed of 18m/s . The cliff is 52m above the water. How long does it take for the stone to fall to the water? With what speed does it strike the water?
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Expert's answer
2012-10-15T12:05:38-0400
The initial horizontal component of velocity doesn't affect the falling time. We know that
H = gT²/2,
and therefore,
T = √(2H/g) = √(2*52[m]/9.8[m/s²]) ≈ 3.3[s].
The vertical speed component of a stone at the moment of landing will be
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